![]() Sang at 16:14 Add a comment 4 Answers Sorted by: 77 SELECT count (City), City FROM table GROUP BY City ORDER BY count (City) OR SELECT count (City) as count, City FROM table GROUP BY City ORDER BY count Ahh, sorry, I was misinterpreting your question. SELECT video_title,CEILING(COUNT(*)/4) as count FROM videosĪnd DATE(wtb_order_archives. 1,888 6 24 34 Exact Answer /questions/26187033/ A. But in either case, it will have to do some kind of sort at some point. ISNULL(c1.count,0)+ISNULL(c2.count,0) as count 1 Answer Sorted by: 1 The optimizer might build a hash table - key values of col, value count. If the link to a subquery fails, the count is NULL, the function IFNULL replaces that with 0. The left join makes sure the every video is selected, and that's why IFNULL(.) is added. I added this reference to the videotitle which makes sure the count is done for every videotitle. If the link to a subquery fails, the count is NULL, the function IFNULL replaces that with 0. There is no reference to a videotitle in this count. ![]() ![]() find shortest city name SET MinCityLen (SELECT MIN (CHARLENGTH (city)) FROM STATION) find longest city name SET MaxCityLen (SELECT MAX (CHARLENGTH (city)) FROM STATION) SELECT city, CHARLENGTH (city) FROM STATION WHERE find. The left join makes sure the every video is selected, and that's why IFNULL(.) is added. Yours is not a case of a very simple query. I added this reference to the video_title which makes sure the count is done for every video_title. There is no reference to a video_title in this count. The COUNT() function returns the number of records returned by a select query. In your query you are adding the results ( SELECT COUNT(*).) from two queries together. ON wtb_order_archives.object_name = _nameĪnd DATE(wtb_order_archives.paid_on) between '' AND ''Īnd also what indexes are the best for such a query? I tried the query below, it's correct but I get an error when trying to select the video title too which comes from videos table, how to select the video title as well? SELECT video_title, If you want descending order (as in this example), you use the DESC keyword. I want the result to contain the video_title and count, which is the transactions count which is all the monthly transactions + (weekly trasactions/4) As usual, you can use both ascending or descending order with ORDER BY. Ascending order doesn't need any keyword because it’s the default, but you can use the ASC keyword if you want to be explicit. If you want descending order (as in this example), you use the DESC keyword. SQL ASC SQL ASC Keyword SQL Keywords Reference ASC The ASC command is used to sort the data returned in ascending order. If an order has a duration of 720, it's a monthly transaction. As usual, you can use both ascending or descending order with ORDER BY. I'm trying to get how many orders happened during a month, if the order has a duration of 168, it's a weekly transaction so I have to divide it by 4, and get the ceiling. 1 (a) I have to question the sensibility of the design that leads to a 'large' query that requires 15 joins.
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